Find the Oxidation Numbers NaH

$N a H$

Step 1

Since $N a$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$N a = 1 (1) = 1$

Step 2

Since $H$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$H = 1 (- 7) = - 7$

Step 3

This is the full list of oxidation states for this molecule.

$N a = 1, H = - 7$