Find the Oxidation Numbers NaK

$N a K$

Step 1

Since $K$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$K = 1 (1) = 1$

Step 2

Since $N a$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$N a = 1 (- 7) = - 7$

Step 3

This is the full list of oxidation states for this molecule.

$K = 1, N a = - 7$