Find the Oxidation Numbers NH_3

$N H_{3}$

Step 1

Since $H$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$H = 3 (1) = 3$

Step 2

Since $N$ is in column $5$ of the periodic table, it will share $5$ electrons and use an oxidation state of $5$ .

$N = 1 (- 3) = - 3$

Step 3

This is the full list of oxidation states for this molecule.

$H = 3, N = - 3$