Find the Oxidation Numbers OCl_2

$O C l_{2}$

Step 1

Since $C l$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$C l = 2 (7) = 14$

Step 2

Since $O$ is in column $6$ of the periodic table, it will share $6$ electrons and use an oxidation state of $6$ .

$O = 1 (- 2) = - 2$

Step 3

This is the full list of oxidation states for this molecule.

$C l = 14, O = - 2$