Find the Oxidation Numbers OsSc

$O s S c$

Step 1

Since $O s$ is in column $0$ of the periodic table, it will share $0$ electrons and use an oxidation state of $0$ .

$O s = 1 (0) = 0$

Step 2

Since $S c$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$S c = 1 (- 5) = - 5$

Step 3

This is the full list of oxidation states for this molecule.

$O s = 0, S c = - 5$