Find the Oxidation Numbers SrK

$S r K$

Step 1

Since $K$ is in column $1$ of the periodic table, it will share $1$ electrons and use an oxidation state of $1$ .

$K = 1 (1) = 1$

Step 2

Since $S r$ is in column $2$ of the periodic table, it will share $2$ electrons and use an oxidation state of $2$ .

$S r = 1 (- 6) = - 6$

Step 3

This is the full list of oxidation states for this molecule.

$K = 1, S r = - 6$