Find the Oxidation Numbers TiCl_4

$T i C l_{4}$

Step 1

Since $T i$ is in column $3$ of the periodic table, it will share $3$ electrons and use an oxidation state of $3$ .

$T i = 1 (3) = 3$

Step 2

Since $C l$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$C l = 4 (- 1) = - 4$

Step 3

This is the full list of oxidation states for this molecule.

$T i = 3, C l = - 4$