Find the Oxidation Numbers XeF_6

$X e F_{6}$

Step 1

Since $X e$ is in column $8$ of the periodic table, it will share $8$ electrons and use an oxidation state of $8$ .

$X e = 1 (8) = 8$

Step 2

Since $F$ is in column $7$ of the periodic table, it will share $7$ electrons and use an oxidation state of $7$ .

$F = 6 (- 1) = - 6$

Step 3

This is the full list of oxidation states for this molecule.

$X e = 8, F = - 6$