Find the Parabola with Focus (1,2) and Directrix y=6 (1,2) , y=6

$(1, 2)$ , $y = 6$

Since the directrix is vertical, use the equation of a parabola that opens up or down.

${(x - h)}^{2} = 4 p (y - k)$

Find the vertex.

The vertex $(h, k)$ is halfway between the directrix and focus. Find the $y$ coordinate of the vertex using the formula $y = \frac{y coordinate of focus + directrix}{2}$ . The $x$ coordinate will be the same as the $x$ coordinate of the focus.

$(1, \frac{2 + 6}{2})$

Simplify the vertex.

Cancel the common factor of $2 + 6$ and $2$ .

Factor $2$ out of $2$ .

$(1, \frac{2 \cdot 1 + 6}{2})$

Factor $2$ out of $6$ .

$(1, \frac{2 \cdot 1 + 2 \cdot 3}{2})$

Factor $2$ out of $2 \cdot 1 + 2 \cdot 3$ .

$(1, \frac{2 \cdot (1 + 3)}{2})$

Cancel the common factors.

Factor $2$ out of $2$ .

$(1, \frac{2 \cdot (1 + 3)}{2 (1)})$

Cancel the common factor.

$(1, \frac{2 \cdot (1 + 3)}{2 \cdot 1})$

Rewrite the expression.

$(1, \frac{1 + 3}{1})$

Divide $1 + 3$ by $1$ .

$(1, 1 + 3)$

Add $1$ and $3$ .

$(1, 4)$

Find the distance from the focus to the vertex.

The distance from the focus to the vertex and from the vertex to the directrix is $| p |$ . Subtract the $y$ coordinate of the vertex from the $y$ coordinate of the focus to find $p$ .

$p = 2 - 4$

Subtract $4$ from $2$ .

$p = - 2$

Substitute in the known values for the variables into the equation ${(x - h)}^{2} = 4 p (y - k)$ .

${(x - 1)}^{2} = 4 (- 2) (y - 4)$

Simplify.

${(x - 1)}^{2} = - 8 (y - 4)$

Find the Parabola with Focus (1,2) and Directrix y=6 (1,2) , y=6

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