Find the Perfect Square Trinomial (3x-7)(3x+10)

$(3 x - 7) (3 x + 10)$

Expand $(3 x - 7) (3 x + 10)$ using the FOIL Method.

Apply the distributive property.

$3 x (3 x + 10) - 7 (3 x + 10)$

Apply the distributive property.

$3 x (3 x) + 3 x \cdot 10 - 7 (3 x + 10)$

Apply the distributive property.

$3 x (3 x) + 3 x \cdot 10 - 7 (3 x) - 7 \cdot 10$

Simplify and combine like terms.

Simplify each term.

Rewrite using the commutative property of multiplication.

$3 \cdot 3 x \cdot x + 3 x \cdot 10 - 7 (3 x) - 7 \cdot 10$

Multiply $x$ by $x$ by adding the exponents.

Move $x$ .

$3 \cdot 3 (x \cdot x) + 3 x \cdot 10 - 7 (3 x) - 7 \cdot 10$

Multiply $x$ by $x$ .

$3 \cdot 3 x^{2} + 3 x \cdot 10 - 7 (3 x) - 7 \cdot 10$

Multiply $3$ by $3$ .

$9 x^{2} + 3 x \cdot 10 - 7 (3 x) - 7 \cdot 10$

Multiply $10$ by $3$ .

$9 x^{2} + 30 x - 7 (3 x) - 7 \cdot 10$

Multiply $3$ by $- 7$ .

$9 x^{2} + 30 x - 21 x - 7 \cdot 10$

Multiply $- 7$ by $10$ .

$9 x^{2} + 30 x - 21 x - 70$

Subtract $21 x$ from $30 x$ .

$9 x^{2} + 9 x - 70$