Find the Perfect Square Trinomial a^2-7a+c

$a^{2} - 7 a + c$

Step 1

Move $- 7 a$ .

$a^{2} + c - 7 a$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $a$ by $2$ and square the result.

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

Apply the product rule to $- \frac{7}{2}$ .

${(- 1)}^{2} {(\frac{7}{2})}^{2}$

Apply the product rule to $\frac{7}{2}$ .

${(- 1)}^{2} \frac{7^{2}}{2^{2}}$

Raise $- 1$ to the power of $2$ .

$1 \frac{7^{2}}{2^{2}}$

Multiply $\frac{7^{2}}{2^{2}}$ by $1$ .

$\frac{7^{2}}{2^{2}}$

Raise $7$ to the power of $2$ .

$\frac{49}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{49}{4}$