Find the Perfect Square Trinomial b^2-4ac

$b^{2} - 4 a c$

Reorder $b^{2}$ and $- 4 a c$ .

$- 4 a c + b^{2}$

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $b$ by $2$ and square the result.

Divide $0$ by $2$ .

$0^{2}$

Raising $0$ to any positive power yields $0$ .

$0$

Add $b^{2} - 4 a c$ and $0$ .

$b^{2} - 4 a c$