Find the Perfect Square Trinomial g^2-20g+c

$g^{2} - 20 g + c$

Step 1

Move $- 20 g$ .

$g^{2} + c - 20 g$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $g$ by $2$ and square the result.

Divide $20$ by $2$ .

${(- 1 \cdot 10)}^{2}$

Multiply $- 1$ by $10$ .

${(- 10)}^{2}$

Raise $- 10$ to the power of $2$ .

$100$