Find the Perfect Square Trinomial m^2+24m

$m^{2} + 24 m$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $m$ by $2$ and square the result.

Divide $24$ by $2$ .

$12^{2}$

Raise $12$ to the power of $2$ .

$144$

Step 2

Add $144$ to get the perfect square trinomial.

$m^{2} + 24 m + 144$