Find the Perfect Square Trinomial m^2+4m

$m^{2} + 4 m$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $m$ by $2$ and square the result.

Divide $4$ by $2$ .

$2^{2}$

Raise $2$ to the power of $2$ .

$4$

Step 2

Add $4$ to get the perfect square trinomial.

$m^{2} + 4 m + 4$