Find the Perfect Square Trinomial m^2+m

$m^{2} + m$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $m$ by $2$ and square the result.

Apply the product rule to $\frac{1}{2}$ .

$\frac{1^{2}}{2^{2}}$

One to any power is one.

$\frac{1}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{1}{4}$

Step 2

Add $\frac{1}{4}$ to get the perfect square trinomial.

$m^{2} + m + \frac{1}{4}$