Find the Perfect Square Trinomial n^2+26n

$n^{2} + 26 n$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $n$ by $2$ and square the result.

Divide $26$ by $2$ .

$13^{2}$

Raise $13$ to the power of $2$ .

$169$

Step 2

Add $169$ to get the perfect square trinomial.

$n^{2} + 26 n + 169$