Find the Perfect Square Trinomial n^2-28n+c

$n^{2} - 28 n + c$

Step 1

Move $- 28 n$ .

$n^{2} + c - 28 n$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $n$ by $2$ and square the result.

Divide $28$ by $2$ .

${(- 1 \cdot 14)}^{2}$

Multiply $- 1$ by $14$ .

${(- 14)}^{2}$

Raise $- 14$ to the power of $2$ .

$196$