Find the Perfect Square Trinomial t^2+18t

$t^{2} + 18 t$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $t$ by $2$ and square the result.

Divide $18$ by $2$ .

$9^{2}$

Raise $9$ to the power of $2$ .

$81$

Step 2

Add $81$ to get the perfect square trinomial.

$t^{2} + 18 t + 81$