Find the Perfect Square Trinomial u^2-6u

$u^{2} - 6 u$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $u$ by $2$ and square the result.

Divide $6$ by $2$ .

${(- 1 \cdot 3)}^{2}$

Multiply $- 1$ by $3$ .

${(- 3)}^{2}$

Raise $- 3$ to the power of $2$ .

$9$

Step 2

Add $9$ to get the perfect square trinomial.

$u^{2} - 6 u + 9$