Find the Perfect Square Trinomial v^2-16v+

$v^{2} - 16 v +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $v$ by $2$ and square the result.

Divide $16$ by $2$ .

${(- 1 \cdot 8)}^{2}$

Multiply $- 1$ by $8$ .

${(- 8)}^{2}$

Raise $- 8$ to the power of $2$ .

$64$

Step 2

Add $64$ to get the perfect square trinomial.

$v^{2} - 16 v + 64$