Find the Perfect Square Trinomial v^2+2v+

$v^{2} + 2 v +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $v$ by $2$ and square the result.

Divide $2$ by $2$ .

$1^{2}$

One to any power is one.

$1$

Step 2

Add $1$ to get the perfect square trinomial.

$v^{2} + 2 v + 1$