Find the Perfect Square Trinomial v^2+8v+

$v^{2} + 8 v +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $v$ by $2$ and square the result.

Divide $8$ by $2$ .

$4^{2}$

Raise $4$ to the power of $2$ .

$16$

Step 2

Add $16$ to get the perfect square trinomial.

$v^{2} + 8 v + 16$