Find the Perfect Square Trinomial w^2-6w+

$w^{2} - 6 w +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $w$ by $2$ and square the result.

Divide $6$ by $2$ .

${(- 1 \cdot 3)}^{2}$

Multiply $- 1$ by $3$ .

${(- 3)}^{2}$

Raise $- 3$ to the power of $2$ .

$9$

Step 2

Add $9$ to get the perfect square trinomial.

$w^{2} - 6 w + 9$