Find the Perfect Square Trinomial x^2-10x+c

$x^{2} - 10 x + c$

Step 1

Move $- 10 x$ .

$x^{2} + c - 10 x$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $10$ by $2$ .

${(- 1 \cdot 5)}^{2}$

Multiply $- 1$ by $5$ .

${(- 5)}^{2}$

Raise $- 5$ to the power of $2$ .

$25$