Find the Perfect Square Trinomial x^2+11x

$x^{2} + 11 x$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Apply the product rule to $\frac{11}{2}$ .

$\frac{11^{2}}{2^{2}}$

Raise $11$ to the power of $2$ .

$\frac{121}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{121}{4}$

Step 2

Add $\frac{121}{4}$ to get the perfect square trinomial.

$x^{2} + 11 x + \frac{121}{4}$