Find the Perfect Square Trinomial x^2-14x+c

$x^{2} - 14 x + c$

Step 1

Move $- 14 x$ .

$x^{2} + c - 14 x$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $14$ by $2$ .

${(- 1 \cdot 7)}^{2}$

Multiply $- 1$ by $7$ .

${(- 7)}^{2}$

Raise $- 7$ to the power of $2$ .

$49$