Find the Perfect Square Trinomial x^2+19x

$x^{2} + 19 x$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Apply the product rule to $\frac{19}{2}$ .

$\frac{19^{2}}{2^{2}}$

Raise $19$ to the power of $2$ .

$\frac{361}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{361}{4}$

Step 2

Add $\frac{361}{4}$ to get the perfect square trinomial.

$x^{2} + 19 x + \frac{361}{4}$