Find the Perfect Square Trinomial x^2-20x+c

$x^{2} - 20 x + c$

Step 1

Move $- 20 x$ .

$x^{2} + c - 20 x$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $20$ by $2$ .

${(- 1 \cdot 10)}^{2}$

Multiply $- 1$ by $10$ .

${(- 10)}^{2}$

Raise $- 10$ to the power of $2$ .

$100$