Find the Perfect Square Trinomial x^2+26x+ ?

$x^{2} + 26 x +$ ?

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $26$ by $2$ .

$13^{2}$

Raise $13$ to the power of $2$ .

$169$

Step 2

Add $169$ to get the perfect square trinomial.

$x^{2} + 26 x + 169$