Find the Perfect Square Trinomial x^2+2x-1

$x^{2} + 2 x - 1$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $2$ by $2$ .

$1^{2}$

One to any power is one.

$1$

Step 2

Combine the opposite terms in $x^{2} + 2 x - 1 + 1$ .

Add $- 1$ and $1$ .

$x^{2} + 2 x + 0$

Add $x^{2} + 2 x$ and $0$ .

$x^{2} + 2 x$