Find the Perfect Square Trinomial x^2-2xy+y^2

$x^{2} - 2 x y + y^{2}$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Cancel the common factor of $2$ .

Cancel the common factor.

${(- \frac{2 y}{2})}^{2}$

Divide $y$ by $1$ .

${(- y)}^{2}$

Simplify the expression.

Apply the product rule to $- y$ .

${(- 1)}^{2} y^{2}$

Raise $- 1$ to the power of $2$ .

$1 y^{2}$

Multiply $y^{2}$ by $1$ .

$y^{2}$

Step 2

Add $y^{2}$ and $y^{2}$ .

$x^{2} - 2 x y + 2 y^{2}$