Find the Perfect Square Trinomial x^2+3/5x

$x^{2} + \frac{3}{5} x$

Step 1

Combine $\frac{3}{5}$ and $x$ .

$x^{2} + \frac{3 x}{5}$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Multiply the numerator by the reciprocal of the denominator.

${(\frac{3}{5} \cdot \frac{1}{2})}^{2}$

Multiply $\frac{3}{5} \cdot \frac{1}{2}$ .

Multiply $\frac{3}{5}$ by $\frac{1}{2}$ .

${(\frac{3}{5 \cdot 2})}^{2}$

Multiply $5$ by $2$ .

${(\frac{3}{10})}^{2}$

Apply the product rule to $\frac{3}{10}$ .

$\frac{3^{2}}{10^{2}}$

Raise $3$ to the power of $2$ .

$\frac{9}{10^{2}}$

Raise $10$ to the power of $2$ .

$\frac{9}{100}$

Step 3

Add $\frac{9}{100}$ to get the perfect square trinomial.

$x^{2} + \frac{3}{5} x + \frac{9}{100}$