Find the Perfect Square Trinomial x^2-40x

$x^{2} - 40 x$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $40$ by $2$ .

${(- 1 \cdot 20)}^{2}$

Multiply $- 1$ by $20$ .

${(- 20)}^{2}$

Raise $- 20$ to the power of $2$ .

$400$

Step 2

Add $400$ to get the perfect square trinomial.

$x^{2} - 40 x + 400$