Find the Perfect Square Trinomial x^2-4x

$x^{2} - 4 x$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $4$ by $2$ .

${(- 1 \cdot 2)}^{2}$

Multiply $- 1$ by $2$ .

${(- 2)}^{2}$

Raise $- 2$ to the power of $2$ .

$4$

Step 2

Add $4$ to get the perfect square trinomial.

$x^{2} - 4 x + 4$