Find the Perfect Square Trinomial x^2-6x+

$x^{2} - 6 x +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $6$ by $2$ .

${(- 1 \cdot 3)}^{2}$

Multiply $- 1$ by $3$ .

${(- 3)}^{2}$

Raise $- 3$ to the power of $2$ .

$9$

Step 2

Add $9$ to get the perfect square trinomial.

$x^{2} - 6 x + 9$