Find the Perfect Square Trinomial x^2+cx+121

$x^{2} + c x + 121$

Step 1

Reorder $x^{2}$ and $c x$ .

$c x + x^{2} + 121$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Apply the product rule to $\frac{c}{2}$ .

$\frac{c^{2}}{2^{2}}$

Raise $2$ to the power of $2$ .

$\frac{c^{2}}{4}$