Find the Perfect Square Trinomial x^2+y^2

$x^{2} + y^{2}$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $x$ by $2$ and square the result.

Divide $0$ by $2$ .

$0^{2}$

Raising $0$ to any positive power yields $0$ .

$0$

Step 2

Add $x^{2} + y^{2}$ and $0$ .

$x^{2} + y^{2}$