Find the Perfect Square Trinomial y^2+0.1y

$y^{2} + 0.1 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $0.1$ by $2$ .

${0.05}^{2}$

Raise $0.05$ to the power of $2$ .

$0.0025$

Step 2

Add $0.0025$ to get the perfect square trinomial.

$y^{2} + 0.1 y + 0.0025$