Find the Perfect Square Trinomial y^2-10y+

$y^{2} - 10 y +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $10$ by $2$ .

${(- 1 \cdot 5)}^{2}$

Multiply $- 1$ by $5$ .

${(- 5)}^{2}$

Raise $- 5$ to the power of $2$ .

$25$

Step 2

Add $25$ to get the perfect square trinomial.

$y^{2} - 10 y + 25$