Find the Perfect Square Trinomial y^2-12y+

$y^{2} - 12 y +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $12$ by $2$ .

${(- 1 \cdot 6)}^{2}$

Multiply $- 1$ by $6$ .

${(- 6)}^{2}$

Raise $- 6$ to the power of $2$ .

$36$

Step 2

Add $36$ to get the perfect square trinomial.

$y^{2} - 12 y + 36$