Find the Perfect Square Trinomial y^2-16y+n

$y^{2} - 16 y + n$

Step 1

Move $- 16 y$ .

$y^{2} + n - 16 y$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $16$ by $2$ .

${(- 1 \cdot 8)}^{2}$

Multiply $- 1$ by $8$ .

${(- 8)}^{2}$

Raise $- 8$ to the power of $2$ .

$64$