Find the Perfect Square Trinomial y^2+18y

$y^{2} + 18 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $18$ by $2$ .

$9^{2}$

Raise $9$ to the power of $2$ .

$81$

Step 2

Add $81$ to get the perfect square trinomial.

$y^{2} + 18 y + 81$