Find the Perfect Square Trinomial y^2+20y

$y^{2} + 20 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $20$ by $2$ .

$10^{2}$

Raise $10$ to the power of $2$ .

$100$

Step 2

Add $100$ to get the perfect square trinomial.

$y^{2} + 20 y + 100$