Find the Perfect Square Trinomial y^2+24y

$y^{2} + 24 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $24$ by $2$ .

$12^{2}$

Raise $12$ to the power of $2$ .

$144$

Step 2

Add $144$ to get the perfect square trinomial.

$y^{2} + 24 y + 144$