Find the Perfect Square Trinomial y^2+26y

$y^{2} + 26 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $26$ by $2$ .

$13^{2}$

Raise $13$ to the power of $2$ .

$169$

Step 2

Add $169$ to get the perfect square trinomial.

$y^{2} + 26 y + 169$