Find the Perfect Square Trinomial y^2-26y+c

$y^{2} - 26 y + c$

Step 1

Move $- 26 y$ .

$y^{2} + c - 26 y$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $26$ by $2$ .

${(- 1 \cdot 13)}^{2}$

Multiply $- 1$ by $13$ .

${(- 13)}^{2}$

Raise $- 13$ to the power of $2$ .

$169$