Find the Perfect Square Trinomial y^2-40y+n

$y^{2} - 40 y + n$

Step 1

Move $- 40 y$ .

$y^{2} + n - 40 y$

Step 2

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $40$ by $2$ .

${(- 1 \cdot 20)}^{2}$

Multiply $- 1$ by $20$ .

${(- 20)}^{2}$

Raise $- 20$ to the power of $2$ .

$400$