Find the Perfect Square Trinomial y^2-6y+

$y^{2} - 6 y +$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $6$ by $2$ .

${(- 1 \cdot 3)}^{2}$

Multiply $- 1$ by $3$ .

${(- 3)}^{2}$

Raise $- 3$ to the power of $2$ .

$9$

Step 2

Add $9$ to get the perfect square trinomial.

$y^{2} - 6 y + 9$