Find the Perfect Square Trinomial y^2+8y

$y^{2} + 8 y$

Step 1

To find the $c$ value $c = {(\frac{b}{2})}^{2}$ , divide the coefficient of $y$ by $2$ and square the result.

Divide $8$ by $2$ .

$4^{2}$

Raise $4$ to the power of $2$ .

$16$

Step 2

Add $16$ to get the perfect square trinomial.

$y^{2} + 8 y + 16$